The amine formed from an amide by means of br | vedclass

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(B) The reaction described is the $	ext{Hofmann bromamide degradation reaction}$.In this reaction,an amide is treated with bromine $(Br_2)$ in the pr

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One less $C$ atom than that of amide

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(B) The reaction described is the $	ext{Hofmann bromamide degradation reaction}$.In this reaction,an amide is treated with bromine $(Br_2)$ in the presence of an aqueous or ethanolic solution of sodium hydroxide $(NaOH)$.This process results in the degradation of the amide to a primary amine containing one carbon atom less than the original amide.For example: $	ext{CH}_3	ext{CONH}_2$ $\xrightarrow{	ext{Br}_2/	ext{NaOH}} 	ext{CH}_3	ext{NH}_2 + 	ext{Na}_2	ext{CO}_3 + 2	ext{NaBr} + 2	ext{H}_2	ext{O}$.Thus,the amine formed has one less $C$ atom than the amide.

The amine formed from an amide by means of bromine and alkali has

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The order of basic strength among the following amines in benzene solution is

The sequence of reagents required to convert aniline to benzoic acid is

Rank the following species in order of decreasing nucleophilicity in a polar protic solvent (most $\to$ least nucleophilic):
$(1) \ CH_3CH_2CH_2O^{-}$,$(2) \ CH_3CH_2CH_2S^{-}$,$(3) \ CH_3CH_2C(=O)O^{-}$

The correct order of basicities of the following compounds is:
$1. CH_3-C(=NH)NH_2$ (Acetamidine)
$2. (CH_3)_2NH$ (Dimethylamine)
$3. CH_3-CH_2-NH_2$ (Ethylamine)
$4. CH_3-CONH_2$ (Acetamide)

The product $(B)$ of this reaction is:

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