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(B) The reaction proceeds in two steps:$1$. Reduction of $p$-nitrophenol with $H_2/Pd$ gives $p$-aminophenol as product $(A)$.$2$. $p$-aminophenol rea

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$N$-($4$-hydroxyphenyl)acetamide

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(B) The reaction proceeds in two steps:$1$. Reduction of $p$-nitrophenol with $H_2/Pd$ gives $p$-aminophenol as product $(A)$.$2$. $p$-aminophenol reacts with acetic anhydride. Since the amino group $(-NH_2)$ is more nucleophilic than the hydroxyl group $(-OH)$,the nitrogen atom attacks the carbonyl carbon of acetic anhydride to form an amide linkage.This results in the formation of $N-(4-hydroxyphenyl)acetamide$,commonly known as Paracetamol.

The product $(B)$ of this reaction is:

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In the given reaction,the product $E$ is:

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