In the reaction sequence Y is CH_3CO_2H xrigh | vedclass

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(B) The reaction sequence is as follows:$1$. $CH_3COOH + NH_3$ $\rightarrow CH_3COONH_4$ $\xrightarrow{\Delta} CH_3CONH_2 (P) + H_2O$$2$. $CH_3CONH_2

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a primary amine with one carbon less than in $P$

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(B) The reaction sequence is as follows:$1$. $CH_3COOH + NH_3$ $\rightarrow CH_3COONH_4$ $\xrightarrow{\Delta} CH_3CONH_2 (P) + H_2O$$2$. $CH_3CONH_2 (P) \xrightarrow{Br_2 / NaOH} CH_3NH_2 (Y) + Na_2CO_3 + NaBr + H_2O$This is the Hofmann bromamide degradation reaction,which converts an amide into a primary amine containing one carbon atom less than the original amide $(P)$.

In the reaction sequence $Y$ is $CH_3CO_2H$ $\xrightarrow[(2) \Delta]{(1) NH_3} P$ $\xrightarrow{Br_2 / NaOH} Y$

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