The order of basicity of the following compou | vedclass

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(A) The correct order of basicity is $IV < I < III < II$.$1$. Compound $IV$ (pyrrole) is the least basic because the lone pair on the nitrogen atom is

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$IV < I < III < II$

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(A) The correct order of basicity is $IV $1$. Compound $IV$ (pyrrole) is the least basic because the lone pair on the nitrogen atom is involved in the aromatic sextet,making it unavailable for protonation.$2$. Compound $I$ ($p$-nitroaniline) is less basic than $III$ (pyridine) because the strong electron-withdrawing $-NO_2$ group decreases the electron density on the nitrogen atom through both $-I$ and $-M$ effects.$3$. Compound $III$ (pyridine) has the nitrogen atom $sp^2$ hybridized,which is more electronegative than the $sp^3$ hybridized nitrogen in aliphatic amines,making it less basic than $II$.$4$. Compound $II$ (cyclohexylamine) is the most basic as it is a primary aliphatic amine with no electron-withdrawing groups attached,and the nitrogen is $sp^3$ hybridized.

The order of basicity of the following compounds in water is:

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