Which set of products will be obtained in the following reactions?
$RCN \xrightarrow{\text{reduction}} (a)$
$RCN \xrightarrow[(ii) H_2O]{(i) CH_3MgBr} (b)$
$RNC \xrightarrow{\text{hydrolysis}} (c)$
$RNH_2 \xrightarrow{HNO_2} (d)$

  • A
    $1^o$ amine,methyl ketone,$1^o$ amine,alcohol
  • B
    $1^o$ amine,methyl ketone,$1^o$ amine,alcohol
  • C
    $2^o$ amine,methyl ketone,$2^o$ amine,acid
  • D
    $2^o$ amine,methyl ketone,$2^o$ amine,aldehyde

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Similar Questions

Product $A$ is

Ethanoic acid on heating with ammonia forms compound $A$ which on treatment with bromine and sodium hydroxide gives compound $B$. Compound $B$ on treatment with $NaNO_2/dil. HCl$ gives compound $C$. The compounds $A, B$ and $C$ respectively are

In the above conversion,the correct sequence of reagents to be added is:

$E \xleftarrow{KOH/Br_2} D \xleftarrow{H_2O_2/OH^{-} \atop (Partial \ Hydrolysis)} C \xleftarrow{NaCN} C_2H_5-Cl$ $\xrightarrow{AgCN} A$ $\xrightarrow{LiAlH_4} B$
What is the relationship between $B$ and $E$?

The product of this Hoffmann bromamide reaction is:

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