What is the major product obtained when dieth | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of diethyl ether $(C_2H_5-O-C_2H_5)$ with concentrated $HI$ at $0^o C$ proceeds via the protonation of the ether oxygen atom.Step $1$

Vedclass · Accepted Answer

Both $C_2H_5OH$ and $C_2H_5I$

Vedclass · Answer

(C) The reaction of diethyl ether $(C_2H_5-O-C_2H_5)$ with concentrated $HI$ at $0^o C$ proceeds via the protonation of the ether oxygen atom.Step $1$: Protonation of ether: $C_2H_5-O-C_2H_5 + HI \rightarrow C_2H_5-O^+(H)-C_2H_5 + I^-$.Step $2$: Nucleophilic attack by $I^-$ on one of the ethyl groups: $I^- + C_2H_5-O^+(H)-C_2H_5 \rightarrow C_2H_5I + C_2H_5OH$.Since both alkyl groups are identical,the reaction produces one molecule of ethyl iodide $(C_2H_5I)$ and one molecule of ethanol $(C_2H_5OH)$.Therefore,both products are formed.

What is the major product obtained when diethyl ether reacts with concentrated $HI$ at $0^o C$?

Similar Questions

The solvent of choice for carrying out a Grignard reaction is

What is $Y$ in the following reaction?
$C_2H_5I + NaOC_2H_5 \longrightarrow X + NaI$
$X + 2HI \xrightarrow{\Delta} 2Y + H_2O$

What are the products $(A)$ and $(B)$ respectively?

The products formed in the following reaction are $C_6H_5-OCH_3 + HI \xrightarrow{\text{heat}}$

The correct statement regarding $X$ and $Y$ formed in the following reaction is
$(CH_3)_3COC_2H_5 \xrightarrow[\Delta]{HI} \text{halide } (X) + \text{alcohol } (Y)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module