What are the products (A) and (B) respectivel | vedclass

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(A) $1$. For the first reaction, the substrate is $3$-hydroxybenzyl alcohol. The reaction with $HBr$ involves the protonation of the side-chain $-OH$

Vedclass · Accepted Answer

$3$-hydroxybenzyl bromide and $3$-hydroxyphenol

Vedclass · Answer

(A) $1$. For the first reaction, the substrate is $3$-hydroxybenzyl alcohol. The reaction with $HBr$ involves the protonation of the side-chain $-OH$ group, followed by the loss of water to form a stable benzylic carbocation. This carbocation then reacts with $Br^-$ to form $3$-hydroxybenzyl bromide. This follows an $S_N1$ mechanism.$2$. For the second reaction, the substrate is $3$-methoxyphenol. The reaction with $HBr$ involves the protonation of the oxygen atom of the methoxy group. The $Br^-$ ion attacks the methyl group, leading to the cleavage of the $C-O$ bond and the formation of $3$-hydroxyphenol (resorcinol) and $CH_3Br$. This follows an $S_N2$ mechanism as the methyl group is sterically unhindered.$3$. Therefore, the products are $3$-hydroxybenzyl bromide and $3$-hydroxyphenol.

What are the products $(A)$ and $(B)$ respectively?

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