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(A) The reaction of ethyl alcohol $(CH_3CH_2OH)$ with bleaching powder $(CaOCl_2)$ involves the formation of chloroform $(CHCl_3)$.Step $1$: Bleaching

Vedclass · Accepted Answer

$CHCl_3$

Vedclass · Answer

(A) The reaction of ethyl alcohol $(CH_3CH_2OH)$ with bleaching powder $(CaOCl_2)$ involves the formation of chloroform $(CHCl_3)$.Step $1$: Bleaching powder reacts with water to produce chlorine: $CaOCl_2 + H_2O \rightarrow Ca(OH)_2 + Cl_2$.Step $2$: Chlorine oxidizes ethyl alcohol to acetaldehyde: $CH_3CH_2OH + Cl_2 \rightarrow CH_3CHO + 2HCl$.Step $3$: Acetaldehyde is chlorinated to form chloral $(CCl_3CHO)$,which then reacts with calcium hydroxide to yield chloroform: $2CH_3CHO + 6Cl_2 \rightarrow 2CCl_3CHO + 6HCl$ and $2CCl_3CHO + Ca(OH)_2 \rightarrow 2CHCl_3 + (HCOO)_2Ca$ (or calcium acetate depending on conditions).The final major organic product is chloroform $(CHCl_3)$.

What is the product obtained by the reaction of ethyl alcohol with bleaching powder?

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