Determine the correct priority order for the | vedclass

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(A) To assign the $R$ or $S$ configuration,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules based on atomic number.$1$. The atoms directly attache

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$OH > CHO > CH_2OH > H$

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(A) To assign the $R$ or $S$ configuration,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules based on atomic number.$1$. The atoms directly attached to the chiral center are $O$ (from $-OH$),$C$ (from $-CHO$),$C$ (from $-CH_2OH$),and $H$.$2$. Atomic numbers: $O (8) > C (6) > H (1)$. Thus,$-OH$ has the highest priority $(1)$ and $-H$ has the lowest priority $(4)$.$3$. Comparing $-CHO$ and $-CH_2OH$: Both are attached to a $C$ atom. We look at the next atoms. $-CHO$ is equivalent to $C$ bonded to $(O, O, H)$ (due to the double bond to $O$). $-CH_2OH$ is $C$ bonded to $(O, H, H)$.$4$. Comparing the lists $(O, O, H)$ and $(O, H, H)$,the first point of difference is the second atom: $O > H$. Therefore,$-CHO$ has higher priority than $-CH_2OH$.$5$. The final priority order is: $-OH (1) > -CHO (2) > -CH_2OH (3) > -H (4)$.

Determine the correct priority order for the following compound to assign the $R$ or $S$ configuration.
$\begin{array}{c} CHO \\ | \\ H-C-OH \\ | \\ CH_2OH \end{array}$

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Determine the correct priority order for the following compound to assign the $R$ or $S$ configuration.$\begin{array}{c} CHO \\ | \\ H-C-OH \\ | \\ CH_2OH \end{array}$