Which of the following is correct for the giv | vedclass

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(D) The molecule has a $C_3$ axis of symmetry because rotating it by $120^\circ$ along an axis passing through the center $P$ and perpendicular to the

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All of these

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(D) The molecule has a $C_3$ axis of symmetry because rotating it by $120^\circ$ along an axis passing through the center $P$ and perpendicular to the plane of the molecule results in an identical form.There is no plane of symmetry $(POS)$ or center of symmetry $(COS)$ in the molecule.Since the molecule lacks $POS$ and $COS$,it is chiral and therefore optically active.Thus,all the given options are correct.

$A$. Acetaldehyde,vinyl alcohol	$1$. Enantiomers
$B$. Eclipsed and staggered ethane	$2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol	$3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine	$4$. Conformational isomers
	$5$. Metamers

Which of the following is correct for the given molecule?

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Match the following:
$A$. Acetaldehyde,vinyl alcohol $1$. Enantiomers
$B$. Eclipsed and staggered ethane $2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol $3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine $4$. Conformational isomers
$5$. Metamers

Which types of isomers of $C_4H_8$ are possible? Give their names and structures.

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