29.5 , mg of an organic compound containing n | vedclass

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(D) $1$. Calculate the total millimoles of $HCl$ taken: $20 \, mL 	imes 0.1 \, M = 2.0 \, mmol$.$2$. Calculate the millimoles of $NaOH$ used for neut

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$23.7$

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(D) $1$. Calculate the total millimoles of $HCl$ taken: $20 \, mL 	imes 0.1 \, M = 2.0 \, mmol$.$2$. Calculate the millimoles of $NaOH$ used for neutralization of excess $HCl$: $15 \, mL 	imes 0.1 \, M = 1.5 \, mmol$.$3$. Millimoles of $HCl$ reacted with $NH_3 = 2.0 - 1.5 = 0.5 \, mmol$.$4$. Since $1 \, mol$ of $NH_3$ reacts with $1 \, mol$ of $HCl$,millimoles of $N = 0.5 \, mmol$.$5$. Mass of nitrogen $= 0.5 	imes 10^{-3} \, mol 	imes 14 \, g/mol = 7 	imes 10^{-3} \, g = 7 \, mg$.$6$. Percentage of nitrogen $= (	ext{Mass of } N / 	ext{Mass of compound}) 	imes 100 = (7 \, mg / 29.5 \, mg) 	imes 100 \approx 23.7\%$.

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