29.5 mg of an organic compound containing ni | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Moles of $HCl$ taken $= 20 	imes 0.1 	imes 10^{-3} = 2 	imes 10^{-3} \ mol$. Moles of $HCl$ neutralized by $NaOH$ solution $= 15 	imes 0.1 	i

Vedclass · Accepted Answer

$23.7$

Vedclass · Answer

(C) Moles of $HCl$ taken $= 20 	imes 0.1 	imes 10^{-3} = 2 	imes 10^{-3} \ mol$. Moles of $HCl$ neutralized by $NaOH$ solution $= 15 	imes 0.1 	imes 10^{-3} = 1.5 	imes 10^{-3} \ mol$. Moles of $HCl$ neutralized by ammonia $= 2 	imes 10^{-3} - 1.5 	imes 10^{-3} = 0.5 	imes 10^{-3} \ mol$. Since $1 \ mol$ of $NH_3$ reacts with $1 \ mol$ of $HCl$,moles of $N = 0.5 	imes 10^{-3} \ mol$. Mass of nitrogen $= 0.5 	imes 10^{-3} \ mol 	imes 14 \ g/mol = 7 	imes 10^{-3} \ g = 7 \ mg$. Percentage of nitrogen $= (	ext{Mass of nitrogen} / 	ext{Mass of compound}) 	imes 100 = (7 \ mg / 29.5 \ mg) 	imes 100 \approx 23.7 \%$.

Similar Questions

In Dumas method,$0.3 \ g$ of an organic compound gave $45 \ mL$ of nitrogen at $STP$. The percentage of nitrogen is

$0.2595 \ g$ of an organic substance in a quantitative analysis yielded $0.35 \ g$ of barium sulphate. The percentage of sulphur in the substance is $...$

In the estimation of sulphur in an organic compound,upon treatment with concentrated $HNO_3$,it is converted into:

Vedclass Test Series

Exam Paper Generator

Online Exam Module