In Dumas method,$0.3 \ g$ of an organic compound gave $45 \ mL$ of nitrogen at $STP$. The percentage of nitrogen is

Dumas method involves the determination of nitrogen content in the organic compound in the form of

$1.2 \ g$ of an organic compound on Kjeldahlization liberates ammonia which consumes $30 \ cm^3$ of $1 \ N \ HCl$. The percentage of nitrogen in the organic compound is:

$0.1 \ g$ of an organic compound was analyzed by the Kjeldahl method. The $NH_3$ produced was absorbed in $30 \ mL$ of $N/5$ $H_2SO_4$. The remaining acid required $20 \ mL$ of $N/10$ $NaOH$ for neutralization. Calculate the percentage of nitrogen in the organic compound.

$29.5 \, mg$ of an organic compound containing nitrogen was digested according to Kjeldahl's method and the evolved ammonia was absorbed in $20 \, mL$ of $0.1 \, M \, HCl$ solution. The excess acid required $15 \, mL$ of $0.1 \, M \, NaOH$ solution for complete neutralization. What is the percentage of nitrogen in the compound?

In the estimation of nitrogen,$0.3 \ g$ of an organic compound was digested,and the evolved ammonia was passed into $100 \ mL$ of $0.1 \ M \ H_2SO_4$. The excess acid required $20 \ mL$ of $0.5 \ M \ NaOH$ for complete neutralization. What is the organic compound?