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(B) The reaction of $1$-butene $(CH_3-CH_2-CH=CH_2)$ with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition rule (Kharasch effec

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$1$-bromobutane

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(B) The reaction of $1$-butene $(CH_3-CH_2-CH=CH_2)$ with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition rule (Kharasch effect or peroxide effect).According to this rule,the negative part of the addendum $(Br^-)$ attaches to the carbon atom of the double bond that has the greater number of hydrogen atoms.Therefore,the reaction is: $CH_3-CH_2-CH=CH_2 + HBr \xrightarrow{	ext{peroxide}} CH_3-CH_2-CH_2-CH_2Br$.The product formed is $1$-bromobutane.

What is the product obtained by the reaction of $1$-butene with $HBr$ in the presence of peroxide?

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