What is the product formed when CH_3-CH=CHBr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of an alkene with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition rule (Kharasch effect or peroxide effect).I

Vedclass · Accepted Answer

$CH_3-CH(Br)-CH_2Br$

Vedclass · Answer

(B) The reaction of an alkene with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition rule (Kharasch effect or peroxide effect).In $CH_3-CH=CHBr$,the double bond is between $C_2$ and $C_3$.According to the anti-Markovnikov rule,the $Br^-$ atom attaches to the carbon atom of the double bond that has more hydrogen atoms.Here,$CH_3-CH=CHBr$ is an unsymmetrical alkene.However,the presence of the $Br$ group on the terminal carbon influences the electron density.Applying the anti-Markovnikov rule,$H$ adds to the carbon with fewer hydrogens and $Br$ adds to the carbon with more hydrogens.Thus,$CH_3-CH=CHBr + HBr \xrightarrow{	ext{peroxide}} CH_3-CH(Br)-CH_2Br$.

What is the product formed when $CH_3-CH=CHBr$ reacts with $HBr$ in the presence of peroxide?

Similar Questions

An isomer of $C_3H_6Cl_2$ on boiling with aqueous $KOH$ gives acetone. Hence,the isomer is

The correct reactivity order for $S_N2$ reaction is:
$(i)$ $CH_3COCH_2Cl$
(ii) $CH_2=CH-CH_2Cl$
(iii) $CH_3CH_2CH_2Cl$

The increasing rate of $S_N1$ reaction in the following compounds is:

Which of the following is an incorrect match?

Among the following,the compound which undergoes the fastest solvolysis is

Vedclass Test Series

Exam Paper Generator

Online Exam Module