When alcoholic KOH is reacted with CH_3CH_2Cl | vedclass

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(A) In the presence of alcoholic $KOH$,the $KOH$ reacts with the ethanol solvent to produce ethoxide ions $(C_2H_5O^{-})$.$KOH + C_2H_5OH \rightarrow

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$C_2H_5O^{-}$

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(A) In the presence of alcoholic $KOH$,the $KOH$ reacts with the ethanol solvent to produce ethoxide ions $(C_2H_5O^{-})$.$KOH + C_2H_5OH \rightarrow C_2H_5O^{-} + K^{+} + H_2O$.Since the ethoxide ion $(C_2H_5O^{-})$ is a much stronger base than the hydroxide ion $(OH^{-})$,it acts as the primary attacking reagent in the dehydrohalogenation (elimination) reaction of $CH_3CH_2Cl$ to form ethene $(CH_2=CH_2)$.

When alcoholic $KOH$ is reacted with $CH_3CH_2Cl$ to form an alkene,which species acts as the attacking reagent?

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