An organic halide is shaken with aqueous NaOH | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The formation of a white precipitate with silver nitrate $(AgNO_3)$ after treatment with $NaOH$ indicates the presence of chloride ions $(Cl^-)$ i

Vedclass · Accepted Answer

$C_6H_5CH_2Cl$

Vedclass · Answer

(B) The formation of a white precipitate with silver nitrate $(AgNO_3)$ after treatment with $NaOH$ indicates the presence of chloride ions $(Cl^-)$ in the solution.$C_6H_5CH_2Cl$ is a primary benzylic halide. It undergoes nucleophilic substitution with aqueous $NaOH$ to form benzyl alcohol and $NaCl$.$C_6H_5CH_2Cl + NaOH_{(aq)} ightarrow C_6H_5CH_2OH + NaCl$When $dil. HNO_3$ and $AgNO_3$ are added to the resulting solution,the $Cl^-$ ions react with $Ag^+$ to form a white precipitate of $AgCl$.$Ag^+ + Cl^- ightarrow AgCl_{(s)} 	ext{ (white ppt)}$$C_6H_5Cl$ (chlorobenzene) does not undergo nucleophilic substitution under these mild conditions,and $C_6H_4(CH_3)Br$ would yield a yellow precipitate of $AgBr$.

An organic halide is shaken with aqueous $NaOH$,followed by the addition of $dil. HNO_3$ and silver nitrate solution,which gives a white precipitate. The substance can be:

Similar Questions

The major product in the given reaction is:

$CH_3-CH_2-Br + Nu^{\Theta} \rightarrow CH_3-CH_2-Nu + Br^{\Theta}$
The decreasing order of the reaction rate with nucleophile $Nu^{\Theta}$ is $Nu^{\Theta} = (I) PhO^{\Theta}; (II) CH_3COO^{\Theta}; (III) OH^{\Theta}; (IV) CH_3O^{\Theta}$

The rate of $S_{N}1$ reaction for the given compounds is:

The maximum number of $RBr$ isomers producing $2-$methylbutane by the given sequence of reactions is $...........$ $(Consider the structural isomers only)$

The compound having the longest $C-Cl$ bond is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module