CH_4 + Cl_2 xrightarrow{UV} CH_3Cl + HCl. Thi | vedclass

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Question

(B) The given reaction is $CH_4 + Cl_2 \xrightarrow{UV} CH_3Cl + HCl$. In this reaction,one hydrogen atom of methane $(CH_4)$ is replaced by a chlorin

Vedclass · Accepted Answer

Substitution reaction

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(B) The given reaction is $CH_4 + Cl_2 \xrightarrow{UV} CH_3Cl + HCl$. In this reaction,one hydrogen atom of methane $(CH_4)$ is replaced by a chlorine atom $(Cl)$ to form chloromethane $(CH_3Cl)$. Such a reaction where an atom or group of atoms is replaced by another atom or group is known as a substitution reaction. Therefore,this is a free radical substitution reaction.

$CH_4 + Cl_2 \xrightarrow{UV} CH_3Cl + HCl$. This reaction is an example of.........

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