Ozonolysis of one mole of a symmetrical alken | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The general reaction for the ozonolysis of a symmetrical alkene is: $R-CH=CH-R + O_3 \rightarrow 2R-CHO$. Given that the product is an aldehyde wi

Vedclass · Accepted Answer

$2$-Butene

Vedclass · Answer

(D) The general reaction for the ozonolysis of a symmetrical alkene is: $R-CH=CH-R + O_3 \rightarrow 2R-CHO$. Given that the product is an aldehyde with a molar mass of $44 \ u$. The general formula for an aldehyde is $R-CHO$. The molar mass of $CHO$ is $12 + 1 + 16 = 29 \ u$. Therefore,the mass of the alkyl group $R$ is $44 - 29 = 15 \ u$. An alkyl group with a mass of $15 \ u$ is a methyl group $(-CH_3)$. Thus,the aldehyde is acetaldehyde $(CH_3CHO)$. Substituting this back into the reaction: $CH_3-CH=CH-CH_3 + O_3 \rightarrow 2CH_3CHO$. The reactant is $2$-butene.

Ozonolysis of one mole of a symmetrical alkene yields two moles of an aldehyde with a molar mass of $44 \ u$. Identify the alkene.

Similar Questions

$P$ is obtained by reductive ozonolysis of which of the following compounds? The reaction is given as:
Cyclohexanone + Acrolein $\xrightarrow{\text{OH}^-, \Delta} P$ (dicarbonyl compound) $(mf = C_{10}H_{14}O_2)$

The reaction of propene with $Cl_2$ at $400-600\,^oC$ gives...........

Which of the following alkenes does $\underline{NOT}$ exhibit cis-trans isomerism?

If the products of ozonolysis are acetone and formaldehyde,what is the starting substance?

Addition of $Br_2$ to $trans-2-butene$ would give a product which is

Vedclass Test Series

Exam Paper Generator

Online Exam Module