In the reaction sequence CH_3CH = CHCH_3 xrig | vedclass

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(D) The reaction is an ozonolysis of but$-2-$ene. Step $1$: $CH_3CH = CHCH_3$ reacts with $O_3$ to form an ozonide intermediate $(A)$. Step $2$: The o

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$CH_3CHO$

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(D) The reaction is an ozonolysis of but$-2-$ene. Step $1$: $CH_3CH = CHCH_3$ reacts with $O_3$ to form an ozonide intermediate $(A)$. Step $2$: The ozonide intermediate $(A)$ undergoes reductive cleavage with $H_2O/Zn$ to produce carbonyl compounds. Reaction: $CH_3CH = CHCH_3 + O_3$ $ightarrow 	ext{ozonide}$ $\xrightarrow{H_2O/Zn} 2CH_3CHO$. Thus,the product $B$ is acetaldehyde $(CH_3CHO)$.

In the reaction sequence $CH_3CH = CHCH_3$ $\xrightarrow{O_3} A$ $\xrightarrow{H_2O/Zn} B$,the alkene forms product $B$. What is product $B$?

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