What is the correct order of basicity for the substituted anilines ($I$ to $IV$)?

Given below are two statements:
Statement-$I$: In Hofmann degradation reaction,the migration of only an alkyl group takes place from carbonyl carbon of the amide to the nitrogen atom.
Statement-$II$: The group is migrated in Hofmann degradation reaction to an electron-deficient nitrogen atom.
In the light of the above statements,choose the most appropriate answer from the options given below:

$A$ primary amine can be converted to an alcohol by the action of

Arrange the following in order of their decreasing acidic strength:
$(I)$ $CH_3NH_3^+$
$(II)$ $C_6H_5NH_3^+$
$(III)$ $[H_2N-C(=NH)-NH_2]H^+$
$(IV)$ $O_2N-C_6H_4-NH_3^+$

In the reaction,Aniline $\xrightarrow[\text{Dil. } HCl]{NaNO_2} P$ $\xrightarrow[NaOH]{\text{Phenol}} Q$,identify $Q$.

Which of the following is the most basic compound?