What is the correct order of acidity for the | vedclass

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(D) The acidity of phenols is determined by the stability of the phenoxide ion formed after the loss of a proton. Electron-withdrawing groups $(EWG)$

Vedclass · Accepted Answer

$IV > III > I > II$

Vedclass · Answer

(D) The acidity of phenols is determined by the stability of the phenoxide ion formed after the loss of a proton. Electron-withdrawing groups $(EWG)$ increase acidity by stabilizing the negative charge,while electron-donating groups $(EDG)$ decrease acidity by destabilizing it.$(I)$ Phenol: Reference compound.$(II)$ $p$-Methylphenol: The $-CH_3$ group is an $EDG$ (via $+I$ and hyperconjugation),which destabilizes the phenoxide ion,making it the least acidic.$(III)$ $m$-Nitrophenol: The $-NO_2$ group is a strong $EWG$ (via $-I$ effect),which stabilizes the phenoxide ion.$(IV)$ $p$-Nitrophenol: The $-NO_2$ group is a strong $EWG$ (via both $-I$ and $-M$ effects),which provides maximum stabilization to the phenoxide ion.Comparing the effects: The $-M$ effect of $-NO_2$ at the para position is more effective than the $-I$ effect at the meta position. Thus,the order of acidity is $IV > III > I > II$.

What is the correct order of acidity for the following compounds?

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