Salicylaldehyde on heating with zinc dust giv | vedclass

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Question

(B) When salicylaldehyde $(2-hydroxybenzaldehyde)$ is heated with zinc dust,the phenolic $-OH$ group is reduced to a hydrogen atom,and the aldehyde gr

Vedclass · Accepted Answer

Benzaldehyde

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(B) When salicylaldehyde $(2-hydroxybenzaldehyde)$ is heated with zinc dust,the phenolic $-OH$ group is reduced to a hydrogen atom,and the aldehyde group is also reduced to a methyl group,resulting in the formation of toluene $(C_6H_5CH_3)$. However,in the context of standard textbook reactions where zinc dust is used to reduce phenolic groups,the product is often identified as benzaldehyde if the reaction conditions specifically target the $-OH$ group. Given the options provided,the most chemically accurate transformation for salicylaldehyde with zinc dust is the reduction of the phenolic $-OH$ to $H$,yielding benzaldehyde $(C_6H_5CHO)$.

Salicylaldehyde on heating with zinc dust gives . . . . . . as the organic product.

Similar Questions

What are $X$ and $Y$ respectively in the following reaction sequence?
$C_6H_5N_2^+X^-$ $\xrightarrow{C_2H_5OH} X$ $\xrightarrow[\text{anhy. } AlCl_3]{CO, HCl} Y$

The major product of the following reaction is:

Phenol and benzoic acid are distinguished by

Assertion $(A)$: $pK_a$ of phenol is $4.19$ and that of benzoic acid is $10$.
Reason $(R)$: Phenoxide ion is stabilised by non-equivalent resonance structures,whereas benzoate ion is stabilised by two equivalent resonance structures.
The correct option among the following is:

Write the nitration and bromination reactions of phenol.

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