When R-CO-NH_2 is treated with Br_2 and KOH,i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction described is the $Hofmann$ $Bromamide$ $Degradation$ reaction.In this reaction,the amide $(R-CO-NH_2)$ reacts with $Br_2$ in the pres

Vedclass · Accepted Answer

$R-CO-NHBr$

Vedclass · Answer

(A) The reaction described is the $Hofmann$ $Bromamide$ $Degradation$ reaction.In this reaction,the amide $(R-CO-NH_2)$ reacts with $Br_2$ in the presence of a strong base $(KOH)$ to form an isocyanate intermediate $(R-N=C=O)$.However,the initial step involves the formation of $N-bromamide$ $(R-CO-NHBr)$ by the replacement of a hydrogen atom on the nitrogen with a bromine atom.Thus,$R-CO-NHBr$ is the key intermediate formed during the process.

When $R-CO-NH_2$ is treated with $Br_2$ and $KOH$,it gives $R-NH_2$ as the major product. Which intermediate is involved in this reaction?

Similar Questions

The reaction of $CH_3NH_2$ with $CH_3MgX$ yields ...........

Which of the following reactions results in azo coupling?

Which of the following compounds will not give isocyanide on reaction with $CHCl_3 + KOH$?

Which of the following amines,on heating with chloroform and ethanolic potassium hydroxide,produces a foul smell?

What is the correct order of basicity for the substituted anilines ($I$ to $IV$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module