Which statement is incorrect regarding the complex $[Cr(NH_3)_6]Cl_3$?

Given below are two statements:
Statement $I$: $[Mn(CN)_6]^{3-}$,$[Fe(CN)_6]^{3-}$ and $[Co(C_2O_4)_3]^{3-}$ are $d^2sp^3$ hybridized.
Statement $II$: $[MnCl_6]^{3-}$ and $[FeF_6]^{3-}$ are paramagnetic and have $4$ and $5$ unpaired electrons,respectively.
In the light of the above statements,choose the correct answer from the options given below:

Identify the $CORRECT$ set of details from the following:
$A$. $[Co(NH_{3})_{6}]^{3+}$: Inner orbital complex; $d^{2}sp^{3}$ hybridized
$B$. $[MnCl_{6}]^{3-}$: Outer orbital complex; $sp^{3}d^{2}$ hybridized
$C$. $[CoF_{6}]^{3-}$: Outer orbital complex; $d^{2}sp^{3}$ hybridized
$D$. $[FeF_{6}]^{3-}$: Outer orbital complex; $sp^{3}d^{2}$ hybridized
$E$. $[Ni(CN)_{4}]^{2-}$: Inner orbital complex; $sp^{3}$ hybridized
Choose the correct answer from the options given below:

In Wilkinson's catalyst,the hybridization of the central metal ion and its shape are respectively:

The geometry of the $[Cu(NH_3)_4]^{2+}$ ion (tetraamminecopper$(II)$ ion) is ................ .

Nickel combines with a uninegative monodentate ligand $(X^{-})$ to form a paramagnetic complex $[NiX_4]^{2-}$. The hybridisation involved and the number of unpaired electrons present in the complex are respectively: