In what ratio does the $yz$-plane divide the line segment joining the points $(-2, 4, 7)$ and $(3, -5, 8)$?

If $A(4,3,5)$,$B(0,-2,2)$,and $C(3,2,1)$ are three points,then the coordinates of the point $D$ where the bisector of $\angle BAC$ meets the side $BC$ are:

If $A(1, 2, -1)$ and $B(-1, 0, 1)$ are given,then the coordinates of point $P$ which divides the line segment $AB$ externally in the ratio $1:2$ are:

Find the coordinates of the point which divides the line segment joining the points $(-2, 3, 5)$ and $(1, -4, 6)$ in the ratio $2:3$ internally.

The point dividing the line segment joining $(3, -2, 1)$ and $(-2, 3, 11)$ in the ratio $2:3$ is

$A(1, 2, 3)$, $B(2, 3, 1)$, and $C(3, 1, 2)$ are three points. If the point $P$ divides $AB$ in the ratio $1:2$ and the point $Q$ divides $BC$ in the ratio $-2:3$, then the distance between $P$ and $Q$ is