Find the coordinates of the point where the line $3x - 2y - 6 = 0$ intersects the $Y$-axis.

The equations of the sides $AB$,$AC$,and $BC$ of a $\triangle ABC$ are respectively $x-3y=0$,$3x-y=0$,and $x+y+4=0$. If $P$ and $Q$ are points on the line $3x-y+k=0$ passing through $B$ such that $PB:BQ=1:1$,then $k=$

Reduce the following equation into slope-intercept form and find its slope and the $y$-intercept.
$x+7y=0$

Write the equation of the lines for which $\tan \theta = \frac{1}{2}$,where $\theta$ is the inclination of the line and $y$-intercept is $-\frac{3}{2}$.

Find the equation of the line which intersects the $y$-axis at a distance of $2$ units above the origin and makes an angle of $30^{\circ}$ with the positive direction of the $x$-axis.

The sum of the squares of the intercepts made by the line $5x - 2y = 10$ on the coordinate axes equals: