Write the equation of the lines for which $\tan \theta = \frac{1}{2}$,where $\theta$ is the inclination of the line and $y$-intercept is $-\frac{3}{2}$.

(A) The slope of the line is given by $m = \tan \theta = \frac{1}{2}$.
The $y$-intercept is given by $c = -\frac{3}{2}$.
Using the slope-intercept form of a line,$y = mx + c$,we substitute the values:
$y = \frac{1}{2}x - \frac{3}{2}$.
Multiplying the entire equation by $2$,we get:
$2y = x - 3$.
Rearranging the terms,we get the equation of the line as:
$x - 2y - 3 = 0$.