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(A) The given equation of the pair of lines is $5x^2 - 7xy - 3y^2 = 0$.Comparing this with the general equation $ax^2 + 2hxy + by^2 = 0$,we get $a = 5

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$3x^2 - 7xy - 5y^2 = 0$

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(A) The given equation of the pair of lines is $5x^2 - 7xy - 3y^2 = 0$.Comparing this with the general equation $ax^2 + 2hxy + by^2 = 0$,we get $a = 5$,$2h = -7$ (so $h = -7/2$),and $b = -3$.The equation of the pair of lines passing through the origin and perpendicular to $ax^2 + 2hxy + by^2 = 0$ is given by $bx^2 - 2hxy + ay^2 = 0$.Substituting the values $a = 5$,$2h = -7$,and $b = -3$ into the formula:$-3x^2 - (-7)xy + 5y^2 = 0$.Multiplying the entire equation by $-1$,we get $3x^2 - 7xy - 5y^2 = 0$.

Find the equation of the pair of lines passing through the origin and perpendicular to the pair of lines given by $5x^2 - 7xy - 3y^2 = 0$.

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