What is the length of the diameter of the cir | vedclass

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(D) The given equation of the circle is $x^2 + y^2 - 4x - 6y + 4 = 0$.Comparing this with the general form $x^2 + y^2 + 2gx + 2fy + c = 0$,we get $2g

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$6$

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(D) The given equation of the circle is $x^2 + y^2 - 4x - 6y + 4 = 0$.Comparing this with the general form $x^2 + y^2 + 2gx + 2fy + c = 0$,we get $2g = -4 \implies g = -2$ and $2f = -6 \implies f = -3$,with $c = 4$.The radius $r$ of the circle is given by the formula $r = \sqrt{g^2 + f^2 - c}$.Substituting the values: $r = \sqrt{(-2)^2 + (-3)^2 - 4} = \sqrt{4 + 9 - 4} = \sqrt{9} = 3$.The diameter $d$ is $2 	imes r = 2 	imes 3 = 6$.

What is the length of the diameter of the circle $x^2 + y^2 - 4x - 6y + 4 = 0$?

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