If the pair of lines $ax^2 + 2(a + b)xy + by^2 = 0$ represent the diameters of a circle and divide the circle into four sectors such that the area of one sector is three times the area of the other,then:

  • A
    $3a^2 - 10ab + 3b^2 = 0$
  • B
    $3a^2 - 2ab + 3b^2 = 0$
  • C
    $3a^2 + 10ab + 3b^2 = 0$
  • D
    $3a^2 + 2ab + 3b^2 = 0$

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