If y = 8x^3 - 60x^2 + 144x + 27 is a decreasi | vedclass

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(B) Given the function $y = 8x^3 - 60x^2 + 144x + 27$. To find the interval where the function is decreasing,we calculate the derivative $\frac{dy}{dx

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$(2, 3)$

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(B) Given the function $y = 8x^3 - 60x^2 + 144x + 27$. To find the interval where the function is decreasing,we calculate the derivative $\frac{dy}{dx}$. $\frac{dy}{dx} = 24x^2 - 120x + 144$. For the function to be decreasing,$\frac{dy}{dx} $24x^2 - 120x + 144 Dividing by $24$,we get $x^2 - 5x + 6 Factoring the quadratic expression,we get $(x - 3)(x - 2) This inequality holds when $x$ lies between the roots $2$ and $3$. Therefore,the interval is $(2, 3)$.

If $y = 8x^3 - 60x^2 + 144x + 27$ is a decreasing function on the interval $(a, b)$,then $(a, b) = $

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