A car moving at a speed of 72 ; km/hr passes | vedclass

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Question

(A) Given: Speed $v = 72 \; km/hr = 72 	imes \frac{5}{18} = 20 \; m/s$,Radius $r = 10 \; m$,Mass $m = 500 \; kg$,Acceleration due to gravity $g = 10

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) Given: Speed $v = 72 \; km/hr = 72 	imes \frac{5}{18} = 20 \; m/s$,Radius $r = 10 \; m$,Mass $m = 500 \; kg$,Acceleration due to gravity $g = 10 \; m/s^2$.At the lowest point $P$ of the curved path,the forces acting on the car are the normal force $R$ (upward) and the weight $mg$ (downward).The net centripetal force is provided by the difference between the normal force and the weight:$R - mg = \frac{mv^2}{r}$$R = mg + \frac{mv^2}{r}$Substituting the values:$R = (500 	imes 10) + \frac{500 	imes (20)^2}{10}$$R = 5000 + \frac{500 	imes 400}{10}$$R = 5000 + 20000 = 25000 \; N$$R = 25 \; kN$.

$A$ car moving at a speed of $72 \; km/hr$ passes through a point $P$ on a curved road with a radius of $10 \; m$. The mass of the car is $500 \; kg$. Find the contact force (normal force) at point $P$ in $kN$. (Take $g = 10 \; m/s^2$)

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