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(A) Let $s_A$ be the displacement of object $A$ and $s_B$ be the displacement of object $B$ at time $t$.For object $A$,initial velocity $u_A = 0$ and

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$2v/a$

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(A) Let $s_A$ be the displacement of object $A$ and $s_B$ be the displacement of object $B$ at time $t$.For object $A$,initial velocity $u_A = 0$ and acceleration is $a$. Using the equation of motion $s = ut + (1/2)at^2$,we get $s_A = (1/2)at^2$.For object $B$,velocity is constant $v$. Thus,$s_B = vt$.Since both objects meet at the same position at time $t$,their displacements must be equal: $s_A = s_B$.Therefore,$(1/2)at^2 = vt$.Dividing both sides by $t$ (assuming $t 
eq 0$),we get $(1/2)at = v$.Solving for $t$,we find $t = 2v/a$.

Object $A$ starts from rest with a constant acceleration $a$. Object $B$ starts from the same position and moves in the same direction as $A$ with a constant velocity $v$. If both meet after time $t$,then $t =$

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