The reading of a pressure gauge connected to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Bernoulli's principle for horizontal flow,the total pressure energy plus kinetic energy per unit volume remains constant: $P_1 + 0 =

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(B) According to Bernoulli's principle for horizontal flow,the total pressure energy plus kinetic energy per unit volume remains constant: $P_1 + 0 = P_2 + \frac{1}{2} ho v^2$.Here,$P_1 = 3.5 	imes 10^5 \, N/m^2$ (pressure when the tap is closed) and $P_2 = 3.0 	imes 10^5 \, N/m^2$ (pressure when the tap is open).The density of water $ho = 10^3 \, kg/m^3$.Rearranging the equation: $\frac{1}{2} ho v^2 = P_1 - P_2$.$v^2 = \frac{2(P_1 - P_2)}{ho}$.Substituting the values: $v^2 = \frac{2(3.5 	imes 10^5 - 3.0 	imes 10^5)}{10^3} = \frac{2(0.5 	imes 10^5)}{10^3} = \frac{10^5}{10^3} = 100$.Therefore,$v = \sqrt{100} = 10 \, m/s$.

The reading of a pressure gauge connected to a closed tap is $3.5 \times 10^5 \, N/m^2$. When the tap is opened,the reading of the pressure gauge falls to $3.0 \times 10^5 \, N/m^2$. The velocity of water is ........ $m/s$.

Similar Questions

According to Bernoulli's equation $\frac{P}{\rho g} + h + \frac{v^2}{2g} = \text{constant}$,the terms $\frac{P}{\rho g}$,$h$,and $\frac{v^2}{2g}$ are generally called respectively:

In the case of a fluid,Bernoulli's theorem expresses the application of the principle of conservation of :

What is the Magnus effect?

Assertion $(A)$: The upper surface of the wing of an aeroplane is made convex and the lower surface is made concave.
Reason $(R)$: The air currents at the top have smaller velocity and thus less pressure at the bottom than at the top.

An application of Bernoulli's equation for fluid flow is found in

Vedclass Test Series

Exam Paper Generator

Online Exam Module