If the average kinetic energy of O_2 (molar m | vedclass

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(C) The average kinetic energy of a gas molecule is given by the formula $K.E. = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is t

Vedclass · Accepted Answer

$0.048$

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(C) The average kinetic energy of a gas molecule is given by the formula $K.E. = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature.Since the average kinetic energy depends only on the temperature $T$ and not on the mass of the gas molecules,the kinetic energy of $N_2$ will be the same as that of $O_2$ at the same temperature.Given that the average kinetic energy of $O_2$ is $0.048 \ eV$,the average kinetic energy of $N_2$ at the same temperature will also be $0.048 \ eV$.

If the average kinetic energy of $O_2$ (molar mass $32$) is $0.048 \ eV$,what is the average kinetic energy of $N_2$ (molar mass $28$) at the same temperature (in $eV$)?

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