A particle of mass 10 g performs simple harm | vedclass

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Question

(C) Given: Mass $m = 10 \ g$,Amplitude $a = 10 \ cm$,Time period $T = 2 \ s$,Displacement $y = 5 \ cm$.Angular frequency $\omega = \frac{2\pi}{T} = \f

Vedclass · Accepted Answer

$375 \pi^2 \ erg$

Vedclass · Answer

(C) Given: Mass $m = 10 \ g$,Amplitude $a = 10 \ cm$,Time period $T = 2 \ s$,Displacement $y = 5 \ cm$.Angular frequency $\omega = \frac{2\pi}{T} = \frac{2\pi}{2} = \pi \ rad/s$.The kinetic energy $K$ of a particle in simple harmonic motion is given by $K = \frac{1}{2} m \omega^2 (a^2 - y^2)$.Substituting the values: $K = \frac{1}{2} 	imes 10 	imes (\pi)^2 	imes (10^2 - 5^2)$.$K = 5 	imes \pi^2 	imes (100 - 25)$.$K = 5 	imes \pi^2 	imes 75$.$K = 375 \pi^2 \ erg$.

$A$ particle of mass $10 \ g$ performs simple harmonic motion with an amplitude of $10 \ cm$ and a time period of $2 \ s$. What is its kinetic energy at a displacement of $5 \ cm$?

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