Two point charges -Q and 2Q are placed at a d | vedclass

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(A) Let the point where the electric field is zero be at a distance $x$ from the charge $-Q$ on the side of the smaller magnitude charge.For two unlik

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At a distance $\frac{R}{(\sqrt{2} - 1)}$ from the $-Q$ charge.

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(A) Let the point where the electric field is zero be at a distance $x$ from the charge $-Q$ on the side of the smaller magnitude charge.For two unlike charges $q_1$ and $q_2$ separated by distance $R$,the null point lies outside the charges on the side of the smaller magnitude charge.Let the distance from $-Q$ be $x$. The distance from $2Q$ will be $R + x$.Equating the magnitudes of the electric fields: $\frac{k|Q|}{x^2} = \frac{k|2Q|}{(R + x)^2}$.Taking the square root on both sides: $\frac{1}{x} = \frac{\sqrt{2}}{R + x}$.$R + x = x\sqrt{2} \Rightarrow R = x(\sqrt{2} - 1)$.$x = \frac{R}{\sqrt{2} - 1}$.This point is located at a distance $\frac{R}{\sqrt{2} - 1}$ from the $-Q$ charge,on the side away from the $2Q$ charge.

Two point charges $-Q$ and $2Q$ are placed at a distance $R$ apart. At what point is the electric field zero?

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