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(B) According to Faraday's first law of electrolysis,the mass $m$ deposited is given by $m = ZIt$,where $Z$ is the electrochemical equivalent,$I$ is t

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$m/2 \, g$

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(B) According to Faraday's first law of electrolysis,the mass $m$ deposited is given by $m = ZIt$,where $Z$ is the electrochemical equivalent,$I$ is the current,and $t$ is the time.For the first case: $m_1 = m$,$I_1 = 4 \, A$,$t_1 = 2 \, minutes = 120 \, s$.So,$m = Z 	imes 4 	imes 120$.For the second case: $I_2 = 6 \, A$,$t_2 = 40 \, s$.Let the mass deposited be $m_2$. Then $m_2 = Z 	imes 6 	imes 40$.Taking the ratio: $\frac{m_2}{m} = \frac{Z 	imes 6 	imes 40}{Z 	imes 4 	imes 120} = \frac{240}{480} = \frac{1}{2}$.Therefore,$m_2 = \frac{m}{2} \, g$.

When a current of $4 \, A$ is passed through a cell for $2 \, minutes$,the mass deposited at the cathode is $m \, g$. If a current of $6 \, A$ is passed through the same cell for $40 \, seconds$,what mass will be deposited at the cathode?

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