Inside a superconducting ring,six identical r | vedclass

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(D) The circuit consists of a central node $O$ connected to nodes $1, 2, 3$ via three resistors of resistance $R$. Additionally,there are three resist

Vedclass · Accepted Answer

Both $(B)$ and $(C)$.

Vedclass · Answer

(D) The circuit consists of a central node $O$ connected to nodes $1, 2, 3$ via three resistors of resistance $R$. Additionally,there are three resistors of resistance $R$ connected between nodes $1-2, 2-3,$ and $3-1$. To find the equivalent resistance between $0$ and $1$,we can use symmetry. Let a current $I$ enter at $0$ and leave at $1$. By symmetry,the currents in the branches $0-2$ and $0-3$ will be equal,say $I'$. Using Kirchhoff's laws or nodal analysis,the equivalent resistance between $0$ and $1$ is found to be $R_{eq} = R/3$. Due to the rotational symmetry of the circuit about the center $O$,the equivalent resistance between $0$ and $1$,$0$ and $2$,and $0$ and $3$ are identical. Thus,both statements $(B)$ and $(C)$ are correct.

Inside a superconducting ring,six identical resistors each of resistance $R$ are connected as shown in the figure. The equivalent resistance$(s)$:

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