(C) The energy of an electron in the $n^{th}$ orbit is given by $E_n = - \frac{13.6}{n^2} \ eV$.For the first orbit $(n = 1)$: $E_1 = - \frac{13.6}{1^

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(C) The energy of an electron in the $n^{th}$ orbit is given by $E_n = - \frac{13.6}{n^2} \ eV$.For the first orbit $(n = 1)$: $E_1 = - \frac{13.6}{1^2} = - 13.6 \ eV$.For the third orbit $(n = 3)$: $E_3 = - \frac{13.6}{3^2} = - \frac{13.6}{9} \approx - 1.51 \ eV$.The energy required to move the electron from the first to the third orbit is $\Delta E = E_3 - E_1$.$\Delta E = - 1.51 - (- 13.6) = 12.09 \ eV$.

Class 12 Physics Atoms Electron Energy and Electron Energy Levels in Hydrogen Atom

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The energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by $E_n = - \frac{13.6}{n^2} \ eV$. How much energy in $eV$ is required to move an electron from the first orbit to the third orbit?

A
$13.6$
B
$3.4$
C
$12.09$
D
$1.51$

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Electron Energy and Electron Energy Levels in Hydrogen Atom

The minimum excitation energy of an electron revolving in the first orbit of hydrogen is (in $eV$)

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If $13.6 \ eV$ energy is required to ionize the hydrogen atom,then the energy required to remove an electron from $n=2$ is (in $eV$)

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The kinetic energy of an electron in the $n^{th}$ orbit of a hydrogen-like species with atomic number $Z$ is $13.6 \frac{Z^2}{n^2} \ eV$. The potential energy of this electron in the same orbit will be:

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The total energy of an electron in an atom in an orbit is $-3.4 \; eV$. Its kinetic and potential energies are,respectively:

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In an atom,an electron requires $47.2 \, eV$ of energy to transition from the $n = 2$ orbit to the $n = 3$ orbit. The atomic number $Z$ of the atom is:

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The energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by $E_n = - \frac{13.6}{n^2} \ eV$. How much energy in $eV$ is required to move an electron from the first orbit to the third orbit?

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The minimum excitation energy of an electron revolving in the first orbit of hydrogen is (in $eV$)

If $13.6 \ eV$ energy is required to ionize the hydrogen atom,then the energy required to remove an electron from $n=2$ is (in $eV$)

The kinetic energy of an electron in the $n^{th}$ orbit of a hydrogen-like species with atomic number $Z$ is $13.6 \frac{Z^2}{n^2} \ eV$. The potential energy of this electron in the same orbit will be:

The total energy of an electron in an atom in an orbit is $-3.4 \; eV$. Its kinetic and potential energies are,respectively:

In an atom,an electron requires $47.2 \, eV$ of energy to transition from the $n = 2$ orbit to the $n = 3$ orbit. The atomic number $Z$ of the atom is:

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