What will be the reading of the voltmeter in | vedclass

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(C) In the given circuit,the capacitor $(X_C = 5 \ \Omega)$ and the inductor $(X_L = 5 \ \Omega)$ are in series with each other.Since $X_L = X_C = 5 \

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(C) In the given circuit,the capacitor $(X_C = 5 \ \Omega)$ and the inductor $(X_L = 5 \ \Omega)$ are in series with each other.Since $X_L = X_C = 5 \ \Omega$,the circuit is in a state of resonance for this part.The voltage across the inductor is $V_L = I X_L$ and the voltage across the capacitor is $V_C = I X_C$.Since they are in series,the current $I$ is the same for both.The net voltage across the series combination of $L$ and $C$ is given by $V_{LC} = |V_L - V_C| = |I X_L - I X_C| = I |X_L - X_C|$.Substituting the values,$V_{LC} = I |5 - 5| = 0 \ V$.Therefore,the voltmeter connected across the $LC$ combination will read $0 \ V$.

What will be the reading of the voltmeter in the given circuit (in $V$)?

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