A compound with the formula C_4H_{10}O reacts | vedclass

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(D) Since the compound reacts with sodium,it must be an alcohol. Upon oxidation,it yields a carbonyl compound that does not reduce Tollen's reagent,wh

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sec-Butyl alcohol

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(D) Since the compound reacts with sodium,it must be an alcohol. Upon oxidation,it yields a carbonyl compound that does not reduce Tollen's reagent,which indicates that the product is a ketone. Primary alcohols oxidize to aldehydes (which reduce Tollen's reagent),whereas secondary alcohols oxidize to ketones (which do not reduce Tollen's reagent). Therefore,the original substance must be a secondary alcohol,which is $sec$-butyl alcohol $(butan-2-ol)$. Reaction: $CH_3CH_2CH(OH)CH_3 \xrightarrow{[O]} CH_3CH_2COCH_3$ $(butan-2-one)$.

$A$ compound with the formula $C_4H_{10}O$ reacts with sodium and upon oxidation gives a carbonyl compound that does not reduce Tollen's reagent. What is the original substance?

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