What is the increasing order of boiling point | vedclass

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(C) The boiling point of a compound depends on the extent of intermolecular hydrogen bonding.$1.$ Hydroxybenzene $(IV)$ has only one $-OH$ group,so it

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$IV < I < II < III$

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(C) The boiling point of a compound depends on the extent of intermolecular hydrogen bonding.$1.$ Hydroxybenzene $(IV)$ has only one $-OH$ group,so it has the lowest boiling point.$2.$ Among the dihydroxybenzenes,$1, 2-$dihydroxybenzene $(I)$ exhibits intramolecular hydrogen bonding,which reduces the extent of intermolecular hydrogen bonding,leading to a lower boiling point compared to the $1, 3-$ and $1, 4-$ isomers.$3.$ $1, 3-$dihydroxybenzene $(II)$ and $1, 4-$dihydroxybenzene $(III)$ exhibit strong intermolecular hydrogen bonding. $1, 4-$dihydroxybenzene has a more symmetrical structure and stronger intermolecular forces,resulting in the highest boiling point.Thus,the increasing order of boiling points is: $IV < I < II < III$.

What is the increasing order of boiling points for the following alcohols?
$I.$ $1, 2-$dihydroxybenzene
$II.$ $1, 3-$dihydroxybenzene
$III.$ $1, 4-$dihydroxybenzene
$IV.$ hydroxybenzene

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What is the increasing order of boiling points for the following alcohols?$I.$ $1, 2-$dihydroxybenzene$II.$ $1, 3-$dihydroxybenzene$III.$ $1, 4-$dihydroxybenzene$IV.$ hydroxybenzene