$CH_3CHO + HCN$ $\xrightarrow{\text{H}^+} CH_3CH(OH)CN$ $\xrightarrow{\text{H}_3\text{O}^+} CH_3CH(OH)COOH$. In the above reaction,a chiral center is generated. What will be the nature of the resulting acid?

Give the conversion of the following:
$(i)$ $but-2-enal$ from $ethanal$
$(ii)$ $Methyl$ $benzoate$ from $benzaldehyde$

Predict the product in the given reaction:
$3-\text{chlorobenzaldehyde} \xrightarrow{50\% \text{KOH}, \Delta} ?$

Considering the following reaction sequence,the correct statement$(s)$ is(are):
$A$. Compounds $P$ and $Q$ are carboxylic acids.
$B$. Compound $S$ decolorizes bromine water.
$C$. Compounds $P$ and $S$ react with hydroxylamine to give the corresponding oximes.
$D$. Compound $R$ reacts with dialkylcadmium to give the corresponding tertiary alcohol.

Ethyl ester $\xrightarrow{CH_3MgBr} P$. What will be the product $P$?

The most appropriate reagent to distinguish between acetaldehyde and formaldehyde is