What will be the product $S$ in the following reaction?
$CH_3COOH$ $\xrightarrow{SOCl_2} P$ $\xrightarrow[Anhyd. AlCl_3]{Benzene} Q$ $\xrightarrow{HCN} R$ $\xrightarrow{HOH} S$

  • A
    $2-$hydroxy$-2-$phenylpropanoic acid
  • B
    $3-$hydroxy$-3-$phenylbutanoic acid
  • C
    $2-$hydroxy$-2-$phenylbutanenitrile
  • D
    $2-$hydroxy$-2-$phenylpropanenitrile

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