$NaOH/H^{+}$ reacts with:

  • A
    $C_6H_5-OCH_3$
  • B
    $CH_3OH$
  • C
    $CH_3COCH_3$
  • D
    $C_2H_5OH$

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Number of products in the given reaction:
$C_6H_5CHO + CH_3CHO \xrightarrow{OH^-} \text{Product}$
will be

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