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(D) For reagent $X$: The starting material is a $\beta$-bromo ketone. Treatment with alcoholic $KOH$ (alc. $KOH$) leads to dehydrohalogenation via an

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alc. $KOH, NaOI$

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(D) For reagent $X$: The starting material is a $\beta$-bromo ketone. Treatment with alcoholic $KOH$ (alc. $KOH$) leads to dehydrohalogenation via an $E2$ mechanism,resulting in the formation of an $\alpha,\beta$-unsaturated ketone.For reagent $Y$: The product contains a carboxylate ion and a yellow precipitate $(CHI_3)$,which is characteristic of the iodoform reaction. This reaction is specific to methyl ketones (or alcohols that can be oxidized to methyl ketones) and is performed using $NaOI$ (sodium hypoiodite).

The suitable reagents $X$ and $Y$,respectively,in the following reactions are:

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