sin (2{sin ^{ - 1}}0.8) = | vedclass

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Question

(A) Let $	heta = \sin^{-1}(0.8)$. Then $\sin 	heta = 0.8 = \frac{4}{5}$.We need to find $\sin(2	heta)$.Using the identity $\sin(2	heta) = 2 \sin \

Vedclass · Accepted Answer

$0.96$

Vedclass · Answer

(A) Let $	heta = \sin^{-1}(0.8)$. Then $\sin 	heta = 0.8 = \frac{4}{5}$.We need to find $\sin(2	heta)$.Using the identity $\sin(2	heta) = 2 \sin 	heta \cos 	heta$.Since $\sin 	heta = \frac{4}{5}$,we have $\cos 	heta = \sqrt{1 - \sin^2 	heta} = \sqrt{1 - (\frac{4}{5})^2} = \sqrt{1 - \frac{16}{25}} = \sqrt{\frac{9}{25}} = \frac{3}{5}$.Therefore,$\sin(2	heta) = 2 	imes \frac{4}{5} 	imes \frac{3}{5} = \frac{24}{25} = 0.96$.

$\sin (2{\sin ^{ - 1}}0.8) = $

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