If aN = {ax : x in N} and bN cap cN = dN,wher | vedclass

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(A) Given $bN = \{b, 2b, 3b, \dots\}$ and $cN = \{c, 2c, 3c, \dots\}$.The intersection $bN \cap cN$ consists of all multiples of both $b$ and $c$.Sinc

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$d = bc$

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(A) Given $bN = \{b, 2b, 3b, \dots\}$ and $cN = \{c, 2c, 3c, \dots\}$.The intersection $bN \cap cN$ consists of all multiples of both $b$ and $c$.Since $b$ and $c$ are coprime,the least common multiple of $b$ and $c$ is $LCM(b, c) = b 	imes c$.Therefore,$bN \cap cN = (bc)N$.Comparing this with $dN$,we get $d = bc$.

If $aN = \{ax : x \in N\}$ and $bN \cap cN = dN$,where $b, c \in N$ are coprime numbers,then:

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